(5x^2)+(-7x^2=)

Solution for (5x^2)+(-7x^2=) equation:

(5x^2)+(-7x^2=)

We move all terms to the left:

(5x^2)+(-7x^2-())=0

We add all the numbers together, and all the variables

5x^2+(-7x^2-())=0


We calculate terms in parentheses: +(-7x^2-()), so:

-7x^2-()

We add all the numbers together, and all the variables

-7x^2

Back to the equation:

+(-7x^2)


We get rid of parentheses

5x^2-7x^2=0

We add all the numbers together, and all the variables

-2x^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-4}=0$